(5w^2-80)/(w^2-2w-80)

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Solution for (5w^2-80)/(w^2-2w-80) equation: 


D( w )

w^2-(2*w)-80 = 0

w^2-(2*w)-80 = 0

w^2-(2*w)-80 = 0

w^2-2*w-80 = 0

w^2-2*w-80 = 0

DELTA = (-2)^2-(-80*1*4)

DELTA = 324

DELTA > 0

w = (324^(1/2)+2)/(1*2) or w = (2-324^(1/2))/(1*2)

w = 10 or w = -8

w in (-oo:-8) U (-8:10) U (10:+oo)

(5*w^2-80)/(w^2-(2*w)-80) = 0

(5*w^2-80)/(w^2-2*w-80) = 0

w^2-2*w-80 = 0

w^2-2*w-80 = 0

DELTA = (-2)^2-(-80*1*4)

DELTA = 324

DELTA > 0

w = (324^(1/2)+2)/(1*2) or w = (2-324^(1/2))/(1*2)

w = 10 or w = -8

(w+8)*(w-10) = 0

(5*w^2-80)/((w+8)*(w-10)) = 0

5*w^2 = 80 // : 5

w^2 = 16

w^2 = 16 // ^ 1/2

abs(w) = 4

w = 4 or w = -4

w in { 4, -4 }

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